The
memmove()
function copies n bytes from memory area
src to memory area dest.
The memory areas may overlap: copying takes place as though
the bytes in
src
are first copied into a temporary array that does not overlap
src
or
dest,
and the bytes are then copied from the temporary array to
dest.
This page is part of release 3.14 of the Linux
man-pages
project.
A description of the project,
and information about reporting bugs,
can be found at
http://www.kernel.org/doc/man-pages/.